Question a:
f(6) = (6)² + 2(6) + 8
f(6) = 36 + 12 + 8
f(6) = 56
Question b:
f(x+4) = (x+4)² + 2(x+4) + 8
f(x+4) = x² + 8x + 16 + 2x + 8 + 8
f(x+4) = x² + 10x + 32
Question c:
f(-x) = (-x)² + 2(-x) + 8
f(-x) = x - 2x + 8
Six tenths (6/10) in decimal form is 0.6
Answer:
ax^2+bx=x(ax+b)
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Step-by-step explanation:
Answer:
f is not defined at x = 3 ⇒ answer (b)
Step-by-step explanation:
∵ f(x) = x² - x - 6/x² - 9 is a rational function
∴ It will be undefined at the values of x of the denominator
∵ The denominator is x² - 9
∵ x² - 9 = 0 ⇒ x² = 9 ⇒ x = ±√9
∴ x = ± 3
∴ f(x) can not be defined at x = 3
∴ The f(x) can not be continuous at x = 3
∴ The answer is (b)
