PLEASE HELP ASAPPP IM TIMED

Mathematics

1 answer:

laila [671]2 years ago

7 0

$\textbf{a).}\\\\r^2-12r+32\\\\=r^2 -8r-4r+32\\ \\=r(r-8) -4(r-8)\\\\=(r-8)(r-4)\\\\\textbf{b).}\\\\5a^2-7a-6\\\\=5a^2-10a+3a-6\\\\=5a(a-2)+3(a-2)\\\\=(a-2)(5a+3)\\\\\textbf{c).}\\\\16g^2+40g+25\\\\=(4g)^2 +2\cdot 5\cdot 4g+5^2\\\\=(4g+5)^2\\\\=(4g+5)(4g+5)$

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What is 4 to the 6th power over 4 to the 8th power?

andreev551 [17]

4⁶ / 4⁸

Since the 'bases' are the same on top and bottom, you can
just subtract the bottom exponent from the top one.

4⁶ / 4⁸
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2 years ago

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Mademuasel [1]

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3 years ago

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aleksley [76]

Hello My Dear Friend!

$9^y-3=8$ 
We move all terms to the left:
 $9^y-3-(8)=0$ 
We add all the numbers together, and all the variables
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We move all terms containing y to the left, all other terms to the right
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$y=11/1$
$y=11$

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3 years ago

–9.45 + 5.4d + 9.01 = –0.1d + 0.66

bulgar [2K]

Answer:

1.838181818181818

Step-by-step explanation:

5.4d + 0.1d = 0.66 + 9.45

5.5d = 10.11

d = 10.11 / 5.5

d = 1.838181818181818

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