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meriva
2 years ago
6

Consider: f(x) = One-half(3)x and g(x) = –One-half(3)–x On a coordinate plane, an exponential function f (x) approaches y = 0 in

quadrant 2 and increases in quadrant 1. How would the graph be affected from f(x) to g(x)? The output values are reflected across the x-axis, but the input values are the same. The output values are the same, but the input values are reflected across the y-axis. The output values are reflected across the x-axis and the input values are reflected across the y-axis. The output values are the same and the input values are the same.
Mathematics
1 answer:
maxonik [38]2 years ago
7 0

Answer:

Numbero 3 (C)

Step-by-step explanation:

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The space provided.
gtnhenbr [62]
The answer is 488 sq cm.

rectangle:

A=lw
A=(22)(17)
A=374

triangle:
A=(1/2)bh
A=(1/2)(19)(22-10)
A=(1/2)(19)(12)
A=(1/2)228
A=114

rectangle + triangle:
374 + 114 = 488
5 0
3 years ago
Which expression is equivalent to logc x^2-1/5x?
fenix001 [56]

Answer:

log(x²-1)-(log5+logx)

Step-by-step explanation:

For this problem we need to make use of two existing logarithmic properties. These are:

  • logM/N is equal to logM - logN
  • logMN is equal to logM+logN

Following the first property, we can simplify the expression to:

log(x²-1)-log5x

Then, we will use the second property to the term 5x. The final form of the expression would then be:

log(x²-1)-(log5+logx)

Thus the answer is log(x²-1)-(log5+logx)....

4 0
3 years ago
If on a scale drawing 240 feet
KATRIN_1 [288]

Answer:

6 feet

Step-by-step explanation:

240 feet : 10 inches

24 feet    : 1 inch

? feet       : 1/4 inch

to get from 1 to a 1/4 you divide by 4, so you do 24 ÷ 4

24 ÷ 4 = 6

6 0
4 years ago
Read 2 more answers
ANSWER ALL QUESTIONS FOR CREDIT
erastova [34]

Answer:

range -> 1.) 99.8 // 2.) 592

mode -> 1.) 3 // 2.) 3.3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Prove that if d|m and d|n, then d|(m+n)
Mila [183]
d\mid m means to say there is some k_1 such that m=dk_1. Similarly, d\mid n is equivalent to saying there exists k_2[/te]x such that [tex]n=dk_2.

Now, m+n=dk_1+dk_2=d(k_1+k_2)=dk_3, i.e. there is some k_3 such that m+n is a multiple of d, i.e. d\mid(m+n).
5 0
4 years ago
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