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kirza4 [7]
2 years ago
9

What is the 30th term of the following arithmetic sequences 17, 21, 25, ...

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
5 0

Answer:

133

Step-by-step explanation:

an = a1 + f × (n-1)

an= 17+4 x (30-1)

an= 17+4 x 29

an= 17+116

an=133

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Arthur Jackson can run 1,500 meters in about 3 1/2 minutes. How many meters per minute is this?
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3 years ago
A/ab-bsquare + b/ab-asquare?​
lord [1]

Answer:

\dfrac{(a+b)}{ab}

Step-by-step explanation:

The given expression is :

\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}

It can be solved as follows :

\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}

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7 0
3 years ago
Please help to solve this please with steps.
Blababa [14]

Answer:

284cm^2

Step-by-step explanation:

first, we split up the shape into seperate sections that we can easily find the areas of.

i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.

we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.

there are 2 of these, so 32 x 2 = 64cm^2.

now, i chose to seperarte the pentagon into a rectangle and a triangle,

and i found the height and width of the rectangle to be (18 - (4+4)) x (8+7), or 10 x 15.

the area of the rectangle is 150cm^2.

now, for the triangle.

the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.

8 + 7 = 15.

22 - 15 = 7.

now we know that the height of the triangle is 7 cm.

from earlier, we also know the base, which is 10cm.

7 x 10 = 70cm^2.

now we add all these together:

70 + 150 + 64 = 284cm^2

4 0
3 years ago
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