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2 years ago

15

The population of a city decreases by 3.9% per year. If this year's population is 200,000, what will next year's population be,

to the nearest individual?

1 answer:

kow [346]2 years ago

6 0

Your answer is 192,000

3.9 percent of 200,000 is 7,800
200,000-7,800=192,000

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Help. What’s the correct answer?

vesna_86 [32]

Answer:

f(g(x)) = -9(sqrt(x + 1) ) + 9

-36

Step-by-step explanation:

This is easier to see if you use the expanded notation.

f(g(x)) = ?

But what that means is that the left most function is f(x) and where every you see an x, you put in a g(x) like so

f(g(x)) = -9(g(x)) + 9 Now substitute the right side of g(x) into the equation for f(x)

f(g(x)) = -9(sqrt(x + 1) ) + 9

Edit to get the numerical answer.

This should be your answer or the expression that will give you the answer.

f(g(24)) = -9(sqrt(24+1) ) + 9

f(g(24)) = -9sqrt(25) +9

f(g(24)) = - 9*5 + 9

f(g(24)) = - 45 + 9

f(g(24)) = - 36

7 0

3 years ago

Read 2 more answers

Can y’all help me w/ 9-14?

Alexxx [7]

Answer:

9. yes

10. no

11. no

12. no

13. yes

14. no

6 0

2 years ago

Joy bought 288 small pieces of candy to share with her friends. She divided the candy into 18 bags. One of the bags will be shar

mariarad [96]

Answer:

32

Step-by-step explanation:

You must divide 288 by 18 and then double the answer you get.

7 0

3 years ago

) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0

2 years ago

9(2.3n+6)+10.45>43.7

kifflom [539]

Answer:

Step-by-step explanation:

9(2.3n+6)+10.45>43.7

(9*2.3n)+(9*6)+10.45>43.7

20.7n+54+10.45>43.7

20.7n+64.45>43.7

7 0

3 years ago