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wolverine [178]
3 years ago
11

How many different possible outcomes are there if you flip 5 coins

Mathematics
1 answer:
Over [174]3 years ago
6 0

Answer:

32 possible outcomes

Step-by-step explanation:

Every time you flip a coin there are two possible outcomes, heads or tails. Therefore we apply the multiplicative rule of counting and show:

2 * 2 * 2 * 2 * 2 = 2^{5} = 32

There are 32 possible outcomes when you flip 5 coins.

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Need help for this please
EastWind [94]
The perimeter is about 82 yards

first, the perimeter of the rectangles is 30*2 = 60 (the 7 is not a part of the overall perimeter so we do not need to add it)

the "perimeter" (circumference) of the 2 semi circles = (22/7)*7 = 22by using the formula C = pi*d (2 semi circles of the same diamter = 1 circle)

now just add the 2 answers
22 + 60

= 82 yards
4 0
3 years ago
How many degrees is a 1/4 turn on the spinner<br>who ever answers is a brainliast
Lelechka [254]
It would most likely be 60degrees cause that’s 1/4 of 180
8 0
3 years ago
What is the answer to this exponent 6*6*6*6*6
Citrus2011 [14]

Answer:

6^5 or 7776

Step-by-step explanation:

6^5 because 6 is multiplied with 6, 5 times. So, it is 6^5.

We can also simplify this number.

=> 6 x 6 x 6 x 6 x 6

=> 36 x 36 x 6

=> 36 x 216

=> 7776

3 0
3 years ago
Read 2 more answers
What is 14 divided by 19,226 with a remainder
jonny [76]

Answer:

1373 r 4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
4(3xy^4)^3/(2x^3y^5)^4
myrzilka [38]

Answer:

\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=\frac{27}{4x^9y^8}

Step-by-step explanation:

Given the expression

\:\:\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}

solving the expression

\:\:\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=4\cdot \:\frac{\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}

             =4\:\frac{27x^3y^{12}}{16x^{12}y^{20}}

              =4\cdot \frac{3^3}{2^4x^9y^8}

The multiply fractions are defined as

\:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

so the expression becomes

                =\frac{3^3\cdot \:4}{2^4x^9y^8}

                =\frac{3^3\cdot \:2^2}{2^4x^9y^8}

                =\frac{3^3}{2^2x^9y^8}

Refining

                 =\frac{27}{4x^9y^8}

Therefore,

\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=\frac{27}{4x^9y^8}            

8 0
3 years ago
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