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IRINA_888 [86]
2 years ago
13

The following box plot shows the class scores on a particular math test:

Mathematics
1 answer:
irina1246 [14]2 years ago
6 0

Answer:

maybe the third one and i would also like to see the box plot

Step-by-step explanation:

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I am a number. I am the
LenaWriter [7]

Answer:

3

Step-by-step explanation:

to find side length of squares take square root of areas

first square side length: 9

second square side length: 6

difference between 9 and 6 is subtraction, 9-6=3

4 0
3 years ago
2.789 in word form and in expanded form
mylen [45]
Word form:
Two and seven hundred eighty-nine thousandths

Expanded form:

2

+ 0.7

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5 0
3 years ago
Read 2 more answers
Factor -8x^3-2x^2-12x-3
inysia [295]

-8x^3-2x^2-12x-3\\\\=-2x^2(4x+1)-3(4x+1)\\\\=(4x+1)(-2x^2-3)\\\\=\boxed{-(4x+1)(2x^2+3)}

5 0
3 years ago
1) -24, -4, 16, 36, ...<br> Find a23
viktelen [127]

We're given the Arithmetic Progression <em>-24, -4, 16, 36 ...</em> .

We know that a term in an AP is generally represented as:

\bf a_n\ =\ a\ +\ (n\ -\ 1)d

where,

  • a = the first term in the sequence
  • n = the number of the term/number of terms
  • d = difference between two terms

We need to find \sf a_2_3.

From the given progression, we have:

  • a = -24
  • n = 23
  • d = (-24 - (-4) = -20

Using these in the formula,

\sf a_2_3\ =\ a\ +\ (n\ -\ 1)d\\\\\\a_2_3\ =\ -24\ +\ (23\ -\ 1)\ \times\ (-20)\\\\\\a_2_3\ =\ -24\ +\ 22\ \times (-20)\\\\\\a_2_3\ =\ -24\ -\ 440\\\\\\\bf a_2_3\ =\ -464

Therefore, the 23rd term in the AP is -464.

Hope it helps. :)

7 0
3 years ago
In your own words explain the phrases "claming first and second place respectively"​
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Answer:

If we divide twice the qualifier of Jose by 4 it results in less than 8. What is Jose's highest grade?

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3 years ago
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