Question

The sum of two numbers is 122. The difference of the first number and twice the second number is 23. Find the two numbers.

Answer 1

Answer:

One is 89 , the other is 33.

Step-by-step explanation:

Set up a system of 2 equations:

x + y = 122

x - 2y = 23        Subtracting:

0 + 3y = 99

y = 33.

So:

x + 33 = 122

x = 122 -33 = 89.

Answer 2

Answer:

first number= 89 and second number= 33

Step-by-step explanation:

here, let the first number be X and the second number be y,then

From the question,

x + y = 122 ---- eq i

x -2y = 23 ----- eq ii

From substitution method,

From eq i,

x + y = 122

or, x =122 - y

Now, putting the vale of x in eq ii,we get,

122 -y -2y = 23

or, -3y = 23-122

or, -3y = -99 (cut minus sign in both sides)

or, y=99/3

or, y = 33

Again, putting the value of y in eq i,we get,

x + 33 = 122

or, x= 122-33

or, x=89