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irinina [24]
2 years ago
8

189.939360828 to 4 decimal places.

Mathematics
1 answer:
bazaltina [42]2 years ago
6 0

Answer:

189.9394

Step-by-step explanation:

Since 6 is >= 5, the 3 thurns into a 4

You might be interested in
The median and mean of these numbers:
aleksandr82 [10.1K]

Answer:

Mean : ≈ 12.7

Median: ≈ 13.5

Step-by-step explanation:

To find the mean you must add all the numbers and divide by the # of numbers in the set.

8+12+13+14+14+15 = 76

76/6 ≈ 12.7

To find the median you have to order the numbers from least to greatest, the middle number should be the median, but in this case two numbers are in the middle.

8, 12, 13, 14, 14, 15

So you have to add 14 and 13, which is 27.

Then divide by 2 which is ≈ 13.5

8 0
3 years ago
Can someone help me with this plz
galina1969 [7]
Let's use a simple way. SPOE, APOE, DPOE, MPOE.

First, isolate the variable.

x5 + 3 = 2
     -3     -3
      x5 = -1/5 (5 divided by -1)


Answer to 5 divided by -1: -5.


A is the answer. (I'm pretty sure.)
If you need further help on steps, feel free to ask by replying.

~Realistic
4 0
3 years ago
681/4 i dont know this
ankoles [38]

Answer:

170.25

Step-by-step explanation:

It's a bit tricky to do not on plain paper, but here:

Just assume the long division symbol looks right

  _1_7_0_.25

4 ) 681

    -4

     2 8

     -2 8

          0  1

The remainder is "1", so you'll just have to write that as either a fraction or decimal, whatever is assigned.

Fraction: 170 1/4

Decimal: 170.25

7 0
3 years ago
Read 2 more answers
If 8 = x + y and y > 0, then x is ___ 8.
qaws [65]
The answer is B because if 0 is < y than 8 would be equal to x

5 0
3 years ago
Find the slope and reduce of p=(3/4,1 1/4) q=(-1/2,-1)
sergij07 [2.7K]
\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;p&({{ \frac{3}{4}}}\quad ,&{{ \frac{1}{4}}})\quad &#10;%   (c,d)&#10;q&({{ -\frac{1}{2}}}\quad ,&{{ -1}})&#10;\end{array}

\bf slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-1-\frac{1}{4}}{-\frac{1}{2}-\frac{3}{4}}\quad \cfrac{\leftarrow LCD=4}{\leftarrow LCD=4}&#10;\\\\\\&#10;\cfrac{\frac{-4-1}{4}}{\frac{-2\cdot 1-3}{4}}\implies \cfrac{\frac{-5}{4}}{\frac{-5}{4}}\implies \cfrac{-5}{4}\cdot \cfrac{4}{-5}\implies 1
7 0
3 years ago
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