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2 years ago

If humans lost the ability to see all color except one, which color would you want to survive?

Mathematics

2 answers:

marta [7]2 years ago

3 0

Answer:

The color blue. There’s many shades of blue and plus blue is my favorite color. I’ll be able to tell if I’m drinking water or not.

Dima020 [189]2 years ago

3 0

Blue . Is the color I like most and even if I can’t see any color seeing blue can make me comfortable

You might be interested in

Ignore the stuff underneath I did it in pen and messed up.

Vinil7 [7]

U didn't mess up....
V = pi * r^2 * h....divide both sides by (pi)r^2
V / (pi)r^2 = h

7 0

3 years ago

Help Please!!!!!!

Vanyuwa [196]

Answer:

centre = (2, - 1), radius = 6

Step-by-step explanation:

Rearrange the equation by placing the x and y terms together and adding 31 to both sides

Given

x² + y² - 4x + 2y - 31 = 0, then

x² - 4x + y² + 2y = 31

Use the method of completing the square

add ( half the coefficient of the x/y term )² to both sides

x² + 2(- 2)x + 4 + y² + 2(1)y + 1 = 31 + 4 + 1

(x - 2)² + (y + 1)² = 36

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r the radius

compare to (x - 2)² + (y + 1)² = 36, then

centre = (2, - 1) and r = $\sqrt{36}$ = 6

3 0

2 years ago

Plz help<br><br><br>If x:6 as 3:9, then x is equal to

sladkih [1.3K]

Answer:

x/6 = 3/9

9x = 18

x = 2

Answer: 2:6 as 3:9

If x:6 as 3:9, then x is equal to

---

Equation:

(x/6) = 3/9

x = 6(3/9)

Step-by-step explanation:

4 0

3 years ago

Do all number lines show only whole number

Lera25 [3.4K]

Answer:

Step-by-step explanation:

no because some numbers could be negative and most number lines also contain 0. whole numbers are positive, non decimal/fractional, real numbers

8 0

2 years ago

Differentiate x^2 e^x logx

zimovet [89]

Product rule:

$\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)$

$=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}$

Power rule:

$\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x$

The exponential function is its own derivative:

$\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x$

Assuming the base of $\log x$ is $e$ , its derivative is

$\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x$

But if you mean a logarithm of arbitrary base $b$ , we have

$y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}$

$\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}$

So we end up with

$2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x$

$=xe^x(2\log x+x\log x+1)$

8 0

2 years ago