Answer:
the building is 28m
Step-by-step explanation:
Answer:
The answer is there are 30 glazed donuts
Step-by-step explanation:
there are 12 donuts to a dozen therefore 12 * 12 = 144 donuts all together.
donuts with chocolate icing

with white icing and sprinkles

donuts with pink icing

Total donuts minus donuts with icing equal glazed donuts

As 1/3 = 2/6 = 3/9 = 4/12
and 2/6 is greater than 1/6
3/9 is greater than 2/9
etc..
So
1/3 is greater than 1/6 ; 2/9 ; ...
Answer:
(a) Percentage of girls = 55
(b) Percentage of boys = 44
Step-by-step explanation:
To find percentage, we multiply the fraction out of the total by 100%.
Percentage of girls =
× 100%
= 55
Percentage of boys =
× 100%
= 44
Answer: x = 0 y = –3
Step-by-step explanation:
We can solve this system by substitution.
use the second equation as a value for x.
Then substitute that value in place of x in the first equation and solve for y.
6x - 5y = 15 becomes
6(y + 3) - 5y = 15 Distribute 6 × parentheses
6y + 18 - 5y = 15 combine like terms
6y -5y + 18 = 15
y + 18 = 15 Subtract 18 from both sides.
y =15 -18
y = –3
Use this value for y in either equation to solve for x
6x - 5(-3) = 15
6x + 15 = 15 Subtract 15 from both sides, divide by 6 (seems silly!)
x = 0
OR in he second equation,
x = -3 + 3
Again, x = 0