6a+ 12b+ 18c
Hope this is correct...plz let me know
Seems like you already have the answer so peace
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
F(x)=12,000(1.08)^x
The answer is the first equation.
The equation increases so 1 is added to 0.08 (8%).
Answer:
5/6
Step-by-step explanation:
When adding fractions, you must ensure the denominator is the same in both fractions.
In this case, the 3 can be multiplied by 2 to equal 6, the other denominator.
When multiplying fractions to create a common denominator, you must multiply the both the numerator and the denominator by the same value, to ensure that the fraction is still equivalent.
2/3 × 2/2 = (2×2)/(3×2) = 4/6
Replace 2/3 with its equivalent 4/6.
Now you will add the numerators together.
1/6 + 4/6 = (1+4)/6 = 5/6
Your final answer is 5/6
