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MArishka [77]
3 years ago
8

62% of 150 is what number

Mathematics
2 answers:
Blababa [14]3 years ago
8 0
First put the percent into decimal form. This is .62.
Then multiply .62 by 150. This is 93. 93 is 62% of 150.
Salsk061 [2.6K]3 years ago
3 0
Put 62/100 = x/150. If you simplify you should be able to get your answer.
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Apple orchard sells Apple's in bags of 10. The orchard sold a total of 2,430 apples one day. How many bags of Apple's was this
zlopas [31]

divide them:

2430/10 = 243 bags

5 0
3 years ago
if in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99%
Dahasolnce [82]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The lifetime (in hours) of a 60-watt light bulb is a random variable that has a Normal distribution with σ = 30 hours. A random sample of 25 bulbs put on test produced a sample mean lifetime of = 1038 hours.

If in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99% confidence, how many randomly selected 60-watt light bulbs should be tested to achieve this result?

Given Information:

standard deviation = σ = 30 hours

confidence level = 99%

Margin of error = 6 hours

Required Information:

sample size = n = ?

Answer:

sample size = n ≈ 165

Step-by-step explanation:

We know that margin of error is given by

Margin of error = z*(σ/√n)

Where z is the corresponding confidence level score, σ is the standard deviation and n is the sample size

√n = z*σ/Margin of error

squaring both sides

n = (z*σ/Margin of error)²

For 99% confidence level the z-score is 2.576

n = (2.576*30/6)²

n = 164.73

since number of bulbs cannot be in fraction so rounding off yields

n ≈ 165

Therefore, a sample size of 165 bulbs is needed to ensure a margin of error not greater than 6 hours.

3 0
3 years ago
Based on past experience, a bank believes that 8.9 % of the people who receive loans will not make payments on time. The bank ha
love history [14]

Answer:

To be able to approximate the sampling distribution with a normal model, it is needed that np \geq 10 and n(1-p) \geq 10, and both conditions are satisfied in this problem.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they will make payments on time, or they won't. The probability of a person making the payment on time is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The sampling distribution can be approximated to a normal model if:

np \geq 10 and n(1-p) \geq 10

Based on past experience, a bank believes that 8.9 % of the people who receive loans will not make payments on time.

This means that p = 0.089

The bank has recently approved 220 loans.

This means that n = 220

What must be true to be able to approximate the sampling distribution with a normal model?

np = 220*0.089 = 19.58 \geq 10

n(1-p) = 220*0.911 = 200.42 \geq 10

To be able to approximate the sampling distribution with a normal model, it is needed that np \geq 10 and n(1-p) \geq 10, and both conditions are satisfied in this problem.

3 0
3 years ago
A plane flies from Dubbo on a bearing of 139° for 852 km, then turns and flies on a bearing of 285° until it is due west of Dubb
Verizon [17]

Answer:

Step-by-step explanation:

So first you add them together which gives you infinity and then you divide infinity by (139+285) then keep doing it until you realise this is a scam

3 0
2 years ago
Solve this riddle
navik [9.2K]
Is it multiple choice
4 0
3 years ago
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