Answer:
The 98% confidence interval for the mean amount of money spent on lunch per week for all students is between $13.3 and $16.7.
Step-by-step explanation:
A confidence interval has the following format.
In which is the mean of the sample and M is the margin of error.
In this problem, we have that:
The 98% confidence interval for the mean amount of money spent on lunch per week for all students is between $13.3 and $16.7.
Answer:
Most likely the answer hope this helps :P
Step-by-step explanation:
1= 10
2= 20
5 = 50
8 = 80
X = 100
The probability that it willtake less than 34 minutes to complete the test is 0.1056
Given mean of 44 minutes and standard deviation of 8 minutes.
We have to find the probability that it will take less than 34 minutes to complete the test.
The probability lies between 0 and 1. The formula to calculate probability is number of items divided by total items but it can also be found through z test calculations.
We are using z test to find the probability.
Z=X-μ/σ
Where μ is sample mean and
σ= standard deviation
Z is z value
First we will find the p value from 34 to 44.
Z=34-44/8
=-10/8
=-1.25
P value for X<34=P(Z<-1.25)
=0.5-0.3944
=0.1056.
Hence the probability that it will take less than 34 minutes is 0.1056.
Learn more about probability at brainly.com/question/24756209
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Answer:
The tax percentage is not needed because the tip was based off the after tax price.
The the total bill was $11
$2.20 divided by 20% = $11
Or
$11 x 20% = $2.20
Step-by-step explanation: