Dan walk 51/2 times around a trail that is 21/2 miles long how far did he walk

Mathematics

1 answer:

Svetach [21]2 years ago

6 0

13 1/4 miles is what I got from multiplying the distance of the trail by the amount of times he walked around it

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What is the difference between (Picture 1) and (picture 2)? A. 0 B. 2 C. 5 D. 6

Vesnalui [34]

Answer:

The difference between the picture is 0 , option A .

Step-by-step explanation:

Given two figures as :

In figure A

The expression is 1 + 3 n , where n lies from 0 to 4

So , let f (n) = 1 + 3 n

Or,f ( n ) = 1 + 3 ×0 = 1 + 0 = 1

f ( 1 ) = 1 + 3 ×1 = 1+ 3 = 4

f ( 2 ) = 1 + 3 ×2 = 1+ 6 = 7

f ( 3 ) = 1 + 3 ×3 = 1+ 9 = 10

f ( 4 ) = 1 + 3 ×4 = 1+ 12 = 13

so, summation of ( 1 + 3 n ) from n = 0 to 4 = 1 + 4 + 7 + 10 + 13 = 35

In figure B

The expression is 3 i - 5 , where i lies from 2 to 6

So , let g (i) = 3 i - 5

Or,g ( 2 ) = 3 ×2 - 5 = 6 - 5 = 1

g ( 3 ) = 3 ×3 - 5 = 9 - 5 = 4

g ( 4 ) = 3 ×4 - 5 = 12 - 5 = 7

f ( 5 ) = 3 ×5 - 5 = 15 - 5 = 10

f ( 6 ) = 3 ×6 - 5 = 18 - 5 = 13

so, summation of ( 3 i - 5 ) from i = 2 to 6 = 1 + 4 + 7 + 10 + 13 = 35

So, The difference between the summation of functions f(n) - g(i) is

f(n) - g(i) = 35 - 35

I.e f(n) - g(i) = 0

Hence The difference between the picture is 0 , option A . Answer

4 0

4 years ago

What is the average rate of change of f(x) = -x2 + 3x + 6 over the interval –3

Rufina [12.5K]

Answer:

$\frac{\Delta y}{\Delta x} =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3$

Step-by-step explanation:

To find the average rate of change of a function over a given interval, basically you need to find the slope. The mathematical definition of the slope is very similar to the one we use every day. In mathematics, the slope is the relationship between the vertical and horizontal changes between two points on a surface or a line. In this sense, the slope can be found using the following expression:

$Average\hspace{3}rate\hspace{3}of\hspace{3}change=Slope=\frac{y_2-y_1}{x_2-x_1} =\frac{f(x_2)-f(x_1)}{x_2-x_1}$