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Rufina [12.5K]
2 years ago
6

How can I solve that problem

Mathematics
1 answer:
drek231 [11]2 years ago
8 0

<u>What do we know so far</u>:

  • 2\frac{2}{3}laps in \frac{4}{15}hour  ⇒ \frac{8}{3}laps in \frac{4}{15}hour

  *we converted the number of laps into improper fractions

        2\frac{2}{3}  = \frac{8}{3}

<u>We want to know the number of laps in an hour</u>

  ⇒ so we must find the rate which ⇒ lap/hour

   lap/hour =\frac{8/3laps}{4/15hours} =\frac{8}{3}*\frac{15}{4}   =\frac{8}{4} *\frac{15}{3} =2*5=10laps/hour

<u>So William can run</u> ⇒ <u>10 laps in one hour</u>

Hope that helps!

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Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

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r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

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Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

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r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

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s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

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In a paragraph, explain whether or not all geometric sequences are exponential functions.
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If f(x) =3x^2 + 1 and g(x)=1-x
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