Answer:
Following are the code to this question:
Counter T = new Counter(1, 100); //creating Counter class object and call its parameterized constructor
Thread T1 = new Thread(new Runnable() //creating Thread object T1.
{
public void run() //define run method
{
T.countRange(); //call countRange method
}
});
Thread T2 = new Thread(new Runnable() //creating another object "T2" of Thread.
{
public void run() //define run method
{
T.countRange(); //call countRange method
}
});
T1.start(); //start Thread T1
T2.start(); //start Thread T2
Explanation:
Description of the above code as follows:
- In the given code, inside the main method the Counter class object "T" is created, that calls its parameterized constructor, which accepts two integer value that is "1 and 100".
- In the next step, thread class object T1 and T2, is created, which uses run method, in which it called the countRange method inside the method a for loop is declared that prints value between parameter value.
- In the last step, the start method is called, which uses the run method to call countRange method.
- For full program code please find the attachment.
Answer:
Layer 4 security and application services, including server load balancing, Secure Sockets Layer (SSL) offloading, firewalling, and intrusion prevention system (IPS) services are provided by the data center <u>aggregation</u> layer.
Explanation:
Consider the given information.
A key point for security and application services is the aggregation layer. In the data centre aggregation layer, the Layer 4 security and application services provide server load balancing, SSL offloading, firewalling, and IPS services.
Layer 4 security and application services, including server load balancing, Secure Sockets Layer (SSL) offloading, firewalling, and intrusion prevention system (IPS) services are provided by the data center <u>aggregation</u> layer.
The answer is URL. ........
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int minn=INT_MAX;
int maxx=INT_MIN;
int n1,n2,n3,n4,n5;
cout<<"enter five Numbers:";
//read 5 Numbers
cin>>n1>>n2>>n3>>n4>>n5;
// find maximum
if(n1>maxx)
maxx=n1;
if(n2>maxx)
maxx=n2;
if(n3>maxx)
maxx=n3;
if(n4>maxx)
maxx=n4;
if(n5>maxx)
maxx=n5;
// find minimum
if(n1<minn)
minn=n1;
if(n2<minn)
minn=n2;
if(n3<minn)
minn=n3;
if(n4<minn)
minn=n4;
if(n5<minn)
minn=n5;
// print maximum and minimum
cout<<"maximum of five numbers is: "<<maxx<<endl;
cout<<"minimum of five numbers is: "<<minn<<endl;
return 0;
}
Explanation:
Declare two variables "minn" & "maxx" and initialize them with INT_MAX and INT_MIN respectively.Then read the five number from user and compare it with "minn" & "maxx" ,if input is greater than "maxx" then update "maxx" or if input is less than "minn" then update the "minn". After all the inputs, "minn" will have smallest and "maxx" will have largest value.
enter five Numbers:5 78 43 55 12
maximum of five numbers is: 78
minimum of five numbers is: 5
