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goblinko [34]
2 years ago
14

WILLGIVEBRAINLIEST,THANKS,5STARS! PLEASE HELP! PLEASE EXPLAIN IN DEPTH!

Mathematics
1 answer:
bearhunter [10]2 years ago
6 0
<h3>Answer:</h3>

x=2

<h3>Solution:</h3>
  • In order to isolate x, we should first of all take the square root of both sides.
  • If we take the square root of the left-hand side, we will get
  • x-\displaystyle\frac{1}{2}
  • How about the right-hand side? Well, we should take the square root of the numerator (9) and the denominator (4)
  • So we have
  • x-\displaystyle\frac{1}{2} =\frac{3}{2}}
  • Move -1/2 to the right:
  • x=-\displaystyle\frac{3}{2} +\frac{1}{2}
  • x=\displaystyle\frac{4}{2}
  • x=2

Hope it helps.

Do comment if you have any query.

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Find the quadratic function that has the vertex (4,5) and passes through the point (8,21) If possible, can you explain the work?
Ganezh [65]
Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!

8 0
3 years ago
A tortoise makes a journey in two parts; it can either walk at 4cm/s or crawl at 3cm/s. If the tottoise walks the first part and
Ugo [173]

Answer:

120

240

Step-by-step explanation:

We call the length of first part x

Length of second part = y

In the first scenario, it took the tortoise 110 sec to walk the first part and crawl the second.

So,

We have this equation,

x/4 + y/3 = 110

We take the LCM

(3x + 4y)/12 = 110

When we cross multiply

3x + 4y = 110x12

3x + 4y = 1320 ----- equation 1

For scenario 2

x/3 + y/4 = 100

When we take the LCM

(4x + 3y)/12 = 100

We cross multiply

4x + 3y = 100x12

4x + 3y = 1200 ------ equation 2

We now have two equations and we will solve for x and y using simultaneous linear equation.

3x + 4y = 1320 ----- 1

4x + 3y = 1200 ----- 2

We subtract equation 2 from 1 to get

- x + y = 120

We make y subject

y = x + 120 ----- 3

We put the value of y in equation 3 into equation 1

3x + 4(x + 120) = 1320

3x + 4x + 480 = 1320

7x + 480 = 1320

7x = 1320-480

7x = 840

We divide through by 7

x = 840/7

x = 120

We put value of x in equation 3

y = x + 120

y = 120 + 120

y = 240

120 and 240 are the lengths of the 2 parts of the journey.

Thanks

5 0
3 years ago
Solve 6y2-5y-6 = 0 using the quadratic formula.
sergejj [24]

Answer:

Ay=3 over 2 or y=-2 over 3

Step-by-step explanation:

the quadratic formula: y={-b±√(b²-4ac)}/2a

In the equation 6y²-5y-6= 0, a=6, b=-5, c= -6

Substituting for the values in the formula we get:

{-(-5)±√[(-5²)-4(6)(-6)}/2(6)

{5±√169}12

={5±13}/12

(5+13)/12=3/2 or (5-13)/12= -2/3

4 0
3 years ago
Read 2 more answers
2 3/4 qt = how many pt
timofeeve [1]
2pt=1qt
1pt=1/2qt
therefor
multiply 2 and 3/4 by 1/2
(2 and 3/4) times 1/2=(2+3/4) times 1/2=2 times 1/2+3/4 times 1/2=2/2+3/8=1+3/8=1 and 3/8 pt
4 0
4 years ago
MathsWatch Question<br> Please Help
seraphim [82]
Make sure you make me brainest

8 0
2 years ago
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