The sampling distribution of the difference in sample means x⁻₁ - x⁻₂ is; 3.5 - 3.5 = 0
<h3>Difference in sample means</h3>
We are told that;
- A fair six-sided die, with sides numbered 1 through 6, will be rolled a total of 15 times.
- x⁻₁ represents the average of the first ten rolls.
- x⁻₂ represents the average of the remaining five rolls.
Now, the average of the largest and lowest numbers of the six sided die is;
E(x) = (6 + 1)/2 = 3.5
Thus, the average mean of the first ten rows is expressed as;
E(x⁻₁) = (n * E(x))/n
E(x⁻₁) = (10 * 3.5)/10
E(x⁻₁) = 3.5
The average mean of the last five rolls will be;
E(x⁻₂) = (n * E(x))/n
E(x⁻₂) = (5 * 3.5)/5
E(x⁻₂) = 3.5
Thus;
x⁻₁ - x⁻₂ = 3.5 - 3.5 = 0
Read more about difference in sample means at; brainly.com/question/16428987
Answer:
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Explanation:
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The only quadrants in which csc x is positive from trigonometric quadrants are; quadrants 1 and 2
<h3>How to Interpret Trigonometric quadrants?</h3>
In trigonometric quadrants, we know that;
In quadrant 1, all functions are positive
In quadrant 2, sin and cosec functions are positive
In quadrant 3, tangent and cotangent functions are positive
In quadrant 4, cos and sec functions are positive.
Thus, we can see that the only quadrants for which csc x is positive are quadrant 1 and quadrant 2.
Read more about Trigonometric quadrants at;brainly.com/question/8120556
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