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pogonyaev
2 years ago
13

ANSWER THE FOLLOWING:​

Mathematics
1 answer:
Bogdan [553]2 years ago
4 0

Answer:

1. (a) 1/12

(b)35/36

(c) 31/36

2. Blue - 1/3

Red- 4/15

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What is this please anyone
xz_007 [3.2K]
The answer is 1.4 x 10^3 Or 1400
Rewrite the equation as
(2x7) x (10^6 x 10^4) then calculate from there to get your answer
4 0
3 years ago
=
timofeeve [1]

Answer:

3x+4

Step-by-step explanation:

f(g(x))=3(x+2)-2

=3x+6-2

=3x+4

6 0
2 years ago
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Terri is rewriting 7 to the 13th power in expanded form. How many factors should she use in her expression?
Pachacha [2.7K]
13


Because the exponent is really just how many factors you have.
For example 2 to the power 5 would have 5 factors in expanded form.
7 0
4 years ago
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In a population distribution, a score of x=57 corresponds to z=-0.25 and a score of x=87 corresponds to z=1.25. Find the mean an
Serggg [28]

Here is dependence between scores and x-values:

Z_i=\dfrac{X_i-\mu}{\sigma},

where \mu is the mean, \sigma is standard deviation and i changes from 1 to 2.

1. When i=1, Z_1=-0.25,\ X_1=57, then

-0.25=\dfrac{57-\mu}{\sigma}.

2. When i=2, Z_2=1.25,\ X_2=87, then

1.25=\dfrac{87-\mu}{\sigma}.

Now solve the system of equations:

\left\{\begin{array}{l}-0.25=\dfrac{57-\mu}{\sigma}\\ \\1.25=\dfrac{87-\mu}{\sigma}.\end{array}\right.

\left\{\begin{array}{l}-0.25\sigma=57-\mu\\ \\1.25\sigma=87-\mu.\end{array}\right.

Subtract first equation from the second:

1.25\sigma-(-0.25\sigma)=87-57,\\ \\1.5\sigma=30,\\ \\\sigma=20.

Then

1.25=\dfrac{87-\mu}{20},\\ \\87-\mu=25,\\ \\\mu=87-25=62.

Answer: the mean is 62, the standard deviation is 20.

3 0
3 years ago
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Sub 2 my channel: Siah Fiah
Nataly_w [17]

Answer:

no

Step-by-step explanation:

From left to right, follow the dots in line 1 with your finger. Count a steady beat out loud, and time your motion so your finger crosses a dot at the end of each beat. Don’t pause at the dots, and move as smoothly as you can. A good way to count is to say or think “1 Mississippi, 2 Mississippi,” and so on. Is your finger moving at a constant rate, or is the rate changing?

7 0
2 years ago
Read 2 more answers
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