2 years ago

What is 100 to the 3rd power

Mathematics

1 answer:

Nimfa-mama [501]2 years ago

7 0

2,500
i hope this helps>,

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A scientest is studying a new super bacteria that is threatening to cause an outbreak. On the first day, there were 5 organisms

ElenaW [278]

Answer:

C. 125

Step-by-step explanation:

Given:

Bacteria on day 1 = 5

On day 2, each bacteria got split into 5.

So, number of bacteria on day 2 = $5\times 5 = 25$

Now, again on day 3, each of the 25 bacteria got split into additional 5 bacteria.

So, number of of bacteria on day 3 = $25\times 5 =125$

Therefore, the population of bacteria on day 3 is 125.

8 0

2 years ago

A water sprinkler sends water out in a circular pattern. How many feet away from the sprinkler can it spread water if the area f

myrzilka [38]

Answer:

The sprinkler can spread water 18 feet away.

Step-by-step explanation:

We are given the following in the question:

Area formed by watering pattern = 1,017.36 square feet

We have to find the how far the sprinkler spread the water.

The sprinkler covers a circular area. We need to find the radius of this circular area to find the how far the sprinkler spread the water.

Area of circle =

$A = \pi r^2$

where r is the radius of the circle.

Putting values, we get,

$1017.36 = 3.14 r^2\\\\r^2 = \dfrac{1017.36}{3.14}\\\\r^2 = 324\\r = \sqrt{324} = 18\text{ feet}$

Thus, the sprinkler can spread water 18 feet away.

6 0

3 years ago

Read 2 more answers

If f(x)=2x, then f^-1(x)=

-BARSIC- [3]

$f(x)=2x\to y=2x\\\\\text{change x and y}\\\\x=2y\\\\\text{solve for y}\\\\2y=x\qquad|:2\\\\y=\dfrac{x}{2}\\\\Answer:\ f^{-1}(x)=\dfrac{x}{2}$

8 0

3 years ago

12g+6=78 thats what i need help with

Mrrafil [7]

I assume you need to solve for g?
12g + 6 = 78
- 6
12g = 72
÷ 12
g = 6
I hope this helps! Let me know if you want me to explain anything :)

4 0

2 years ago

Read 2 more answers

Complete the table to describe the model. The model will have a verbal description, a division expression, and a fraction.

NARA [144]

Answer:

what I dont even know whT your talking about. could you please explain your question a bit more?? then maybe I could help you out

5 0

3 years ago