All categories

2 years ago

What is the standard deviation of the population: Use the stdevp function in the Desmos graphing calculator.

Mathematics

1 answer:

Mice21 [21]2 years ago

8 0

The standard deviation of the given data is 3.5

<h3 /><h3>How to calculate the standard deviation of data?</h3>

Standard deviation is used to determine the rate of dispersion of data with respect to the mean.

The formula for calculating the standard deviation of data is given as:

$\sigma = \sqrt{\frac{\sum (x-\overline x)^2}{n-1} }$

Given the data below:

10.4, 10.3, 11.7, 11.1, 8, 4.4, 2.6, 1.8, 2.5, 4.4, 7.3, 9.5

Using the stdevp calculator the standard deviation is calculated as:

σ = √12.405

σ = 3.5

Hence the standard deviation of the given data is 3.5

Learn more on standard deviation here: brainly.com/question/12402189

You might be interested in

Ask Your Teacher The circumference of a sphere was measured to be 90 cm with a possible error of 0.5 cm. (a) Use differentials t

SCORPION-xisa [38]

Answer:

a) 28,662 cm² max error

0,0111 relative error

b) 102,692 cm³ max error

0,004 relative error

Step-by-step explanation:

Length of cicumference is: 90 cm

L = 2*π*r

Applying differentiation on both sides f the equation

dL = 2*π* dr ⇒ dr = 0,5 / 2*π

dr = 1/4π

The equation for the volume of the sphere is

V(s) = 4/3*π*r³ and for the surface area is

S(s) = 4*π*r²

Differentiating

a) dS(s) = 4*2*π*r* dr ⇒ where 2*π*r = L = 90

Then

dS(s) = 4*90 (1/4*π)

dS(s) = 28.662 cm² ( Maximum error since dr = (1/4π) is maximum error

For relative error

DS´(s) = (90/π) / 4*π*r²

DS´(s) = 90 / 4*π*(L/2*π)² ⇒ DS(s) = 2 /180

DS´(s) = 0,0111 cm²

b) V(s) = 4/3*π*r³

Differentiating we get:

DV(s) = 4*π*r² dr

Maximum error

DV(s) = 4*π*r² ( 1/ 4*π*) ⇒ DV(s) = (90)² / 8*π²

DV(s) = 102,692 cm³ max error

Relative error

DV´(v) = (90)² / 8*π²/ 4/3*π*r³

DV´(v) = 1/240

DV´(v) = 0,004

3 0

3 years ago

Read 2 more answers

I neeed helpppppppp please

Nat2105 [25]

Answer:

I think its aas

Step-by-step explanation:

6 0

3 years ago

Simplify 4 to the seventh power over 5 squared all raised to the third power . (4 points)

julsineya [31]

Answer: The answer is C, 4 to the 21st over 5 to the 6th power.

4 0

2 years ago

Can someone help, me

Radda [10]

The answer to #5 is 33.

8 0

3 years ago

Read 2 more answers

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

3 years ago