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wolverine [178]

2 years ago

13

The coordinates of the point P:(2,2), Q:(6,2), R:(6,5), S:(2,5) represent the vertices of a rectangle. What is the perimeter, in

units of rectangle PQRS?

2 answers:

erik [133]2 years ago

6 0

Answer:

Hope the picture will help you....

Anuta_ua [19.1K]2 years ago

4 0

Answer:

C. 14 units

Step-by-step explanation:

Perimeter is the distance around the outside of the shape. Add up all the sides. See image.

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Solve using the standard algorithm <br> 1.03 +0.08

nataly862011 [7]

Answer:

1.11

Step-by-step explanation:

1.03+0.08=1.11

4 0

3 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

4 years ago

4/5x = 3<br> please solve for x

san4es73 [151]

Answer:

x=15/4 or x=3.75

Step-by-step explanation:

4/5*x=3

4/5=0.8

0.8*3.75=3

3 0

3 years ago

Julie baked cupcakes for her family at home and for a party at school. She iced 4 cupcakes with red frosting, 2 cupcakes with or

bonufazy [111]

5 different vorieties

8 0

4 years ago

For the function given, state the middle line; f(t) = 40cos (80t + 20)

Digiron [165]

In the standard form of the equation

$\\ \ f(t)=Acos[b(t\pm c)]+k\\ \\$

The middle line =k

For our given problem

f(t) = 40cos (80t + 20)

On comparison we get k=0

Hence middle line=0

8 0

3 years ago