Answer:
17.32m ; 110°
Step-by-step explanation:
Distance between X and Z
To calculate the distance between X and Z
y^2 = x^2 + z^2 - (2xz)*cosY
x = 20, Z = 10
y^2 = 20^2 + 10^2 - (2*20*10)* cos60°
y^2 = 400 + 100 - (400)* 0.5
y^2 = 500 - 200
y^2 = 300
y = sqrt(300)
y = 17.32m
Bearing of Z from X:
Using cosine rule :
Cos X = (y^2 + z^2 - x^2) / 2yz
Cos X = (300 + 100 - 400) / (2 * 20 '*10)
Cos X = 0 / 400
Cos X = 0
X = cos^-1 (0)
X = 90°
Bearing of Z from X
= 20° + X
= 20° + 90°
= 110°
6/8a+4,6-2/4a. I think that this is the answer.
Answer:
₹2520
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 10%/100 = 0.1 per year,
then, solving our equation
I = 12600 × 0.1 × 2 = 2520
I = ₹ 2,520.00
The simple interest accumulated
on a principal of ₹ 12,600.00
at a rate of 10% per year
for 2 years is ₹ 2,520.00.
Answer:
n = - 12
Step-by-step explanation:
n/9 + 2/3 = - 2/3
n/9 = - 2/3 - 2/3
n/9 = - 4/3
n = 9(- 4/3)
n = -36/3
n = - 12
Answer:
The expression that represents the population of elk is:
. It'll take 6 years for the population to reach 1,458 individuals.
Step-by-step explanation:
Since the number of elks triples every year and starts at
, then after the first year the population will be:

While on the second year, it'll be:

On the third year:

And so on, therefore the expression that describes the population of elk as the years passes is:

If we want to know the number of years until the population reach 1,458 elk, we need to apply this value to the left side of the equation and solve for t.

The population will reach 1,458 elk in 6 years.