Use the given line of best fit to approximate the rate of change relative to the scatter plot below.

One serving of Gooey Gushers provides 12% of the daily value of vitamin C. Tim ate 312 servings of Gooey Gushers.

Studentka2010 [4]

Answer:

a) Given expression,

12% of 312

Since 100% of 312 = 312

⇒ 10% of 312 = 31.2,

⇒ 1% = 3.12

⇒ 2% = 2 × 3.12 = 6.24

So, 12% of 312 = 10% of 312 + 2% of 312

= 31.2 + 6.24

= 37.44

b) Given,

Total number of servings = 312,

The percentage of vitamin C in each serving = 12%,

Thus, the total amount of the vitamin C in 312 servings = 12% of 312

$=\frac{12\times 312}{100}$

$=\frac{3744}{100}$

= 37.44,

Hence, the question can be asked about the total amount of the vitamin C.

6 0

3 years ago

Surface area is the sum of the areas of all the surfaces of a three-dimensional object.

Dmitry [639]

Answer: True

Think of a 3D box. It has 6 faces and the surface area is the total of all six individual rectangular faces. This idea applies to any polyhedron.

3 0

3 years ago

Solve for x: 2x-4/5=x+4

shepuryov [24]

2x-4=5x+20

-3x=24

x=-8

3 0

3 years ago

Read 2 more answers

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

3 years ago

Which statement is true

weqwewe [10]

The answers are
a) the domain is all real numbers
d) the input to an exponential function is the exponent
e) the base represents the multiplicative rate of change

hope this helps :)

5 0

3 years ago