Find the value of x.* 20 48 36 60

Rectangle EFGH is shown with a line IJ passing vertically through the center of the rectangle.

Dovator [93]

C) shift six units up

6 0

3 years ago

Read 2 more answers

It’s this correct 1 2

oksian1 [2.3K]

Make sure that you put a line over the 1s on #2

I can not see the fraction on #1

3 0

4 years ago

Un huerto escolar tiene una superficie de 4dam2 500m2 y se requiere dividir en seis parcelas rectangulares de igual area ¿ cuant

vitfil [10]

Answer:

Cada parcela tendrá una extensión de 150 metros cuadrados.

Step-by-step explanation:

De acuerdo con el enunciado el huerto escolar tiene una extensión de 4 decámetros y 500 metros cuadrados.

Tengamos presente que un decámetro es igual a 100 metros cuadrados, entonces el huerto escolar tiene un área total de 900 metros cuadrados. Si dividimos esa área en seis parcelas de igual extensión, tenemos que:

$x = \frac{900\,m^{2}}{6}$

$x = 150\,m^{2}$

Cada parcela tendrá una extensión de 150 metros cuadrados.

7 0

3 years ago

Be sure to answer all parts. List the evaluation points corresponding to the midpoint of each subinterval to three decimal place

gayaneshka [121]

Answer:

The Riemann Sum for $\int\limits^5_4 {x^2+4} \, dx$ with n = 4 using midpoints is about 24.328125.

Step-by-step explanation:

We want to find the Riemann Sum for $\int\limits^5_4 {x^2+4} \, dx$ with n = 4 using midpoints.

The Midpoint Sum uses the midpoints of a sub-interval:

$\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f\left(\frac{x_0+x_1}{2}\right)+f\left(\frac{x_1+x_2}{2}\right)+f\left(\frac{x_2+x_3}{2}\right)+...+f\left(\frac{x_{n-2}+x_{n-1}}{2}\right)+f\left(\frac{x_{n-1}+x_{n}}{2}\right)\right)$

where $\Delta{x}=\frac{b-a}{n}$

We know that a = 4, b = 5, n = 4.

Therefore, $\Delta{x}=\frac{5-4}{4}=\frac{1}{4}$

Divide the interval [4, 5] into n = 4 sub-intervals of length $\Delta{x}=\frac{1}{4}$

$\left[4, \frac{17}{4}\right], \left[\frac{17}{4}, \frac{9}{2}\right], \left[\frac{9}{2}, \frac{19}{4}\right], \left[\frac{19}{4}, 5\right]$

Now, we just evaluate the function at the midpoints:

$f\left(\frac{x_{0}+x_{1}}{2}\right)=f\left(\frac{\left(4\right)+\left(\frac{17}{4}\right)}{2}\right)=f\left(\frac{33}{8}\right)=\frac{1345}{64}=21.015625$

$f\left(\frac{x_{1}+x_{2}}{2}\right)=f\left(\frac{\left(\frac{17}{4}\right)+\left(\frac{9}{2}\right)}{2}\right)=f\left(\frac{35}{8}\right)=\frac{1481}{64}=23.140625$

$f\left(\frac{x_{2}+x_{3}}{2}\right)=f\left(\frac{\left(\frac{9}{2}\right)+\left(\frac{19}{4}\right)}{2}\right)=f\left(\frac{37}{8}\right)=\frac{1625}{64}=25.390625$

$f\left(\frac{x_{3}+x_{4}}{2}\right)=f\left(\frac{\left(\frac{19}{4}\right)+\left(5\right)}{2}\right)=f\left(\frac{39}{8}\right)=\frac{1777}{64}=27.765625$