we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
How to find the dimensions of the large rectangle?
First, we know that the large rectangle is the smaller rectangle rescaled, with a scale factor k = 4.
This means that each dimension of the smaller rectangle must be multiplied by 4 to get the correspondent dimension on the larger rectangle.
The dimensions of the smaller rectangle are:
l₁ = 12in
w₁ = 8in
Then the correspondent dimensions of the large rectangle are:
l₂ = 4*12in = 48 in
w₂= 4*8in = 32in
Now, the area of the large rectangle is given by the product between the two dimensions, we will get:
A₂ = 48in*32in = 1,536 in^2
Then, we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
If you want to learn more about rectangles:
brainly.com/question/17297081
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What are you solving for? X or y or do you just need to put it in slope intercept form
Answer:
Factor x2 + 9x + 18.
A) (x - 3)(x - 6)
B) (x + 2)(x + 9)
C) (x + 3)(x + 6)
D) (x - 2)(x - 9)
Step-by-step explanation:
(x+3)(x+6)=x^2+6x+3x+18=x^2+9x+18
The answer to this is .960
Good morning ☕️
Answer:
<h2>32° and 58°</h2>
-by-step explanation:
Let x be the measure of angle 1
and y be the measure of angle 2
The Two angles are complementary
means
x + y = 90
their difference is 26 degrees
means
x - y = 26
x + y = 90 (1)
x - y = 26 (2)
(1) - (2) ⇒2y = 64 ⇒ y =32°
therefore x = y + 26 = 58°
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:)
