Answer:
4 sec
Step-by-step explanation:
let y = 0 which is the height when the rocket hits the ground
-3t^2 + 6t + 24 = 0
-3(t^2 - 2t - 8) = 0
-3(t - 4)(t + 2) = 0
t = 4 or t = -2
time cannot be negative, so t = 4 sec
The rise is 2 and the run is 3
5 - 6 = -1
2 + 7 = 9
-1 × 9 = -9
-9 would be the simplified answer.
Hope this helps!
