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3 years ago

Solve for y 3x+6y=30

Mathematics

2 answers:

balandron [24]3 years ago

6 0

Answer:

the answer= y=5−x/2

belka [17]3 years ago

5 0

Answer: $y=-\frac{1}{2} x+5$

Step-by-step explanation:

We need to isolate y by itself

Step 1) Subtract 3x from both sides

$3x+6y=30\\3x-3x+6y=30-3x\\6y=30-3x$

Step 2) Divide both sides by 6 to isolate y

$6y=30-3x\\\frac{6y}{6} =\frac{30}{6}-\frac{3x}{6} \\y=5-\frac{1}{2}x$

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Step-by-step explanation:

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A rectangle has 4 sides where it's opposite sides are congruent.

So if one side has measurement w, then there is another side that has measurement w.

If there is one side that has measurement l, then there is another side that has measurement l.

So if you add w+w+l+l you get 2w+2l.

They are giving us that the perimeter is P, so P=2w+2l.

we are being asking to solve for l.

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First step: Isolate term that contains the l, so get 2l by itself first.

We are going to subtract 2w on both sides giving us:

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Now that we have 2l by itself it is time to perform the last step in getting l by itself.

Second step: Divide both sides by 2.

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$l=\frac{P-2w}{2}=\frac{P}{2}-\frac{2w}{2}=\frac{P}{2}-w$ .

I don't know your options but I have solve for l in terms of P and w

and got $l=\frac{P}{2}-w$ .

Please let me know if you have further questions with this problem.

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