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ivanzaharov [21]
3 years ago
14

Solve for y 3x+6y=30

Mathematics
2 answers:
balandron [24]3 years ago
6 0

Answer:

the answer= y=5−x/2

belka [17]3 years ago
5 0

Answer: y=-\frac{1}{2} x+5

Step-by-step explanation:

We need to isolate y by itself

Step 1) Subtract 3x from both sides

3x+6y=30\\3x-3x+6y=30-3x\\6y=30-3x

Step 2) Divide both sides by 6 to isolate y

6y=30-3x\\\frac{6y}{6} =\frac{30}{6}-\frac{3x}{6}  \\y=5-\frac{1}{2}x

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Work out the area of this circle.<br> Give your answer in terms of it and state its units.<br> 6 mm
andrey2020 [161]

Answer:

113.142 mm

Step-by-step explanation:

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To solve the equation X - 62 = 123, you would ?
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6 0
3 years ago
Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

6 0
3 years ago
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