Step-by-step explanation:

all the details are in the attachment.
That's not a linear system, but you have an awesome school system for giving you this problem.

Multiply by 6xy to clear the fractions.

That's a second degree equation, also known as a conic. That one happens to be a hyperbola.


Let's clear the fractions from the second equation, multiplying out common denominator xy:


We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.
Substituting,





We have to rule out x=0 because it's in the denominator.


Answer: (44/19, 33/20)
Answer:
The volume of hemisphere is <u>19.4 cubic meter</u>.
Step-by-step explanation:
Given:
A hemisphere is with a radius of 2.1 m.
Now, to find the hemisphere volume with radius 2.1 m.

So, we put formula to get the volume of hemisphere:

<u><em>Hence, the rounded to the nearest tenth of a cubic meter is 19.4 cubic meter.</em></u>
Therefore, the volume of hemisphere is 19.4 cubic meter.
In system A, the first equation multiply by 4
8x - 4y = 12 (1st)
3x + 4y = 10 (2nd)
--------------------add
11x = 22
So answer is B.
Answer:
There are two choices for angle Y:
for
,
for
.
Step-by-step explanation:
There are mistakes in the statement, correct form is now described:
<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>
The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:
(1)
If we know that
,
and
, then we have the following second order polynomial:

(2)
By the Quadratic Formula we have the following result:

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:



1) 
![Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]](https://tex.z-dn.net/?f=Y%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B18%5E%7B2%7D%2B14%5E%7B2%7D-15.193%5E%7B2%7D%7D%7B2%5Ccdot%20%2818%29%5Ccdot%20%2814%29%7D%20%5Cright%5D)

2) 
![Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]](https://tex.z-dn.net/?f=Y%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B18%5E%7B2%7D%2B14%5E%7B2%7D-8.424%5E%7B2%7D%7D%7B2%5Ccdot%20%2818%29%5Ccdot%20%2814%29%7D%20%5Cright%5D)

There are two choices for angle Y:
for
,
for
.