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tangare [24]
3 years ago
13

A right triangle includes one algae that measures 14º. what is the measure of the third angle

Mathematics
2 answers:
Anni [7]3 years ago
8 0

Answer:

B. 76 degrees

Step-by-step explanation:

EVERY triangle's angles add up to 180 degrees. We already know that since it's a right triangle, one of the angles equals 90 degrees (that's a right angle) and they give us the second angle measurement, 14 degrees. If we add those two angle measures together and subtract them from 180, we should get the measure of the third angle as our answer.

14 + 90 = 104

180 - 104 = 76

Therefore, the third and final angle in this right triangle equals 76, so your answer is B. I hope this helps! Have a lovely day!! :)

Sedbober [7]3 years ago
3 0

Answer: B. 76

Step-by-step explanation: A right triangle is 180 degrees. It has an angle of 90 since it is a right triangle. 90 + 14 = 104. 180 - 104 = 76

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Molodets [167]

Step-by-step explanation:

\sqrt{35} =\sqrt{5} *\sqrt{7};

all the details are in the attachment.

3 0
2 years ago
Can anyone plzzzz help me with this question of linear equation in two varaiable plzzzzzz... Its very important... Plz solve it
kotegsom [21]

That's not a linear system, but you have an awesome school system for giving you this problem.

\dfrac 5 y - \dfrac 2 x = \dfrac{13}6

Multiply by 6xy to clear the fractions.

30x - 12y = 13 xy

That's a second degree equation, also known as a conic.  That one happens to be a hyperbola.  

30x = y(13 x +12)

y = \dfrac{30x}{13 x + 12}

Let's clear the fractions from the second equation, multiplying out common denominator xy:

\dfrac {36} x - \dfrac {24} y = 1

36y - 24 x = xy

We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.

Substituting,

36 \left( \dfrac{30x}{13 x + 12} \right) - 24 x = x \left( \dfrac{30x}{13 x + 12} \right)

36(30x) -24 x(13x + 12) = 30x^2

1080 x - 312 x^2- 288 x = 30x^2

x(792 - 342 x)= 0

x = 0 \textrm{ or } x=792/342 = \dfrac{44}{19}

We have to rule out x=0 because it's in the denominator.

y = \dfrac{30x}{13 x + 12} = \dfrac{30(44/19)}{13(44/19)+12}

y = \dfrac{33}{20}

Answer: (44/19, 33/20)

8 0
3 years ago
What is the volume of a hemisphere with a radius of 2.1 m, rounded to the nearest tenth of a cubic meter?
Art [367]

Answer:

The volume of hemisphere is <u>19.4 cubic meter</u>.

Step-by-step explanation:

Given:

A hemisphere is with a radius of 2.1 m.

Now, to find the hemisphere volume with radius 2.1 m.

Radius\ (r) = 2.1 m.

So, we put formula to get the volume of hemisphere:

Volume=\frac{2}{3} \pi r^3\ \ \ \ \ (Taking\ the\ value\ of\ \pi =3.14)\\\\Volume=\frac{2}{3} \times 3.14\times 2.1^3\\\\Volume=\frac{2}{3} \times 3.14\times 9.26\\\\Volume=19.384\ cubic\ meter.

<u><em>Hence, the rounded to the nearest tenth of a cubic meter is 19.4 cubic meter.</em></u>

Therefore, the volume of hemisphere is 19.4 cubic meter.

3 0
3 years ago
Need help can someone help me with this question
REY [17]

In system A, the first equation multiply by 4

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7 0
4 years ago
In Triangle XYZ, measure of angle X = 49° , XY = 18°, and
marissa [1.9K]

Answer:

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X (1)

If we know that X = 49^{\circ}, XY = 18 and YZ = 14, then we have the following second order polynomial:

14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}

XZ^{2}-23.618\cdot XZ +128 = 0 (2)

By the Quadratic Formula we have the following result:

XZ \approx 15.193\,\lor\,XZ \approx 8.424

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y

\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}

Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)

1) XZ \approx 15.193

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 54.987^{\circ}

2) XZ \approx 8.424

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 27.008^{\circ}

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

6 0
3 years ago
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