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2 years ago

a bug population doubles every 5 days. If you start with 6 bugs, how many bugs will there be in 35 days

Mathematics

1 answer:

Shtirlitz [24]2 years ago

5 0

Answer:

768 bugs

Step-by-step explanation:

You can rewrite this problem as a function as time where the bug population is f(x), and x is the number of days since the start.

f(x)=6*2^(x/5)

Here, the 6 represents the number of bugs that you start with, the two shows that they double every day, and the /5 shows that they double every 5 days.

By plugging in 35, you get 6*2^7, which is 768.

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Answer:

1) $\displaystyle\frac{5}{18}\approx27.78\%$

2) $\displaystyle\frac{4}{7}\approx57.14\%$

3) $\displaystyle \frac{13}{16}=81.25\%$

Step-by-step explanation:

We are given a two-way frequency table. Using the table, we will determine the probability for each case.

Question 1)

P(A Student With A Part Time Job Without A Car)

Using the first column, the total number of students that have a part time job is 78+30=108.

Likewise, using the first column, we can see that out of those 108 students, 30 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{30}{108}=\frac{5}{18}\approx27.78\%$

Question 2)

P(No Car | Does Not Have A Part Time Job)

Remember that the vertical line means conditional probability.

So, we want the probability of a student having no car given that they do not have a part time job.

Using the second column, we can see that the total number of students that do not have a part time job is 18+24=42.

Likewise, using the second column, 24 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{24}{42}=\frac{4}{7}\approx57.14\%$

Question 3)

P(Part Time Job | Car)

So, we want to probability of a student having a part time job given that they have a car.

Using the first row, the total students that have a car is 78+18=96.

And of those 96 students, 78 have a part time job.

Hence, the probability that a student with a car has a part time job is given by:

$\displaystyle P=\frac{78}{96}=\frac{13}{16}=81.25\%$

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