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3 years ago

Will award brainliest for the correct answer!

Mathematics

1 answer:

Darina [25.2K]3 years ago

5 0

The answer is x^2 (or x squared) + 10x + 25 units. Pretty sure this is a multiple choice question.

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WHICH ANSWER GOES WHERE ON THE NUMBER LINE ? I will give 11 points and brainliest!!!

anzhelika [568]

I don't know what your asking

8 0

3 years ago

Read 2 more answers

Suppose that circles A and B have a central angle measuring 40°. Additionally, circle A has a radius of 5 2 ft and the radius of

vladimir1956 [14]

It is 9/4π ft².

Since the central angle is 40°, this is 40/360 = 1/9 of the circle.

The area of the circle is given by A=πr²; since r=9/2, we have
A=π(9/2)² = 81/4π

Multiplying this by 1/9,
81/4π(1/9) = 81/36π = 9/4π

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3 years ago

5. Which two triangles in problems 1-4 are similar? Explain.<br> Help please

Shkiper50 [21]

Answer:

Triangle 1(ABC) and Triangle 3(XYZ) are similar since all their angles are equal

In Traingle XYZ m of angle Y is 85 degree..

Hope it helps u...

4 0

3 years ago

Which statement best reflects the solution(s) of the equation?

Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0$

Now, factoring the term:

$x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2$

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

5 0

4 years ago

Simplify 2(5+3x) + (x+10)

xz_007 [3.2K]

Answer:

7x + 20

I hope I helped :D

Step-by-step explanation:

8 0

3 years ago