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2 years ago

10

What is the slope of the line that contains the points (-1, 2) and (3, 3)?

1 answer:

sweet [91]2 years ago

7 0

Answer:

$\text Slope = \frac{1}{4}$

Step-by-step explanation:

the slope of the line that passes through the points

$\large A\left( x_{1},y_{1}\right) \text{and} \ B\left( x_{2},y_{2}\right)$

$\large \text{slope} =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

the slope of the line that contains the points (-1, 2) and (3, 3) is :

$\Longrightarrow \text{slope} =\frac{3-2}{3-\left( -1\right) }= \frac{1}{4}$

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Multiply:<br>(x+y)by (x+y)<br>a+b by a^2-b^2<br>(a+5) by (a^2-2a-3)<br>(a^2-ab+b^3) by (a+b)

Law Incorporation [45]

Answer:

Multiply:

$(x+y)by (x+y)$

$: \implies(x + y)(x + y)$

$: \implies \: x(x + y) + y(x + y)$

$: \implies {x}^{2} + xy + xy + {y}^{2}$

$: \implies{x}^{2} + 2xy + {y}^{2}$

Multiply:

$a+b \: by \: a^2-b^2$

$: \implies( {a}^{2} + {b}^{2} ) \times (a + b)$

$: \implies \: {a}^{2} (a + b) - {b}^{2} (a + b)$

$: \implies \: {a}^{3} + {a}^{2} b - {ab}^{2} - {b}^{3}$

Multiply:

$(a+5) by (a^2-2a-3)$

$: \implies{(a + 5) \times ( {a}^{2} - 2a - 3) }$

$: \implies \: a({a}^{2} - 2a - 3) + 5( {a}^{2} - 2a - 3)$

$: \implies(a \times {a}^{2} - a \times 2a - a \times 3) + (5 \times {a}^{2} - 5 \times 2a - 5 \times 3)$

$: \implies{a}^{3} - {2a}^{2} - 3a + 5 {a}^{2} - 10a - 15$

$: \implies{ {a}^{3} + {3a}^{2} - 13a - 15}$

Multiply:

$(a^2-ab+b^3) by (a+b)$

$: \implies{(a + b) \times ( {a}^{2} - ab + {b}^{3} )}$

$: \implies \: a( {a}^{2} - ab + {b}^{3}) + b( {a}^{2} - ab + {b}^{3} )$

$: \implies {a}^{3} - {a}^{2} b + a {b}^{3} + {a^2b} - {ab}^{2} + {b}^{4}$

$: \implies{ {a}^{3}+ab^3 - ab^2+ {b}^{4} }$

Step-by-step explanation:

$\blue{ \frak{Seolle_{aph.rodite}}}$

7 0

2 years ago

4. Find the distance between the two points. Round to the nearest tenth if necessary.

Archy [21]

Answer:

Distance = 7.8 units

Step-by-step explanation:

In coordinate geometry, the distance between the 2 points is given by

$Distance = \sqrt{(x1-x2)^{2} + (y1-y2)^{2} }$

where (x1,y1) and (x2,y2) are coordinates of the 2 points.

Above the 2 points given are, (-2,-1) and (3,5).

<em>x1 = -2 , y1 = -1 , x2 = 3, y2 = 5</em>

<em> $Distance = \sqrt{((-2)-(3))^{2} + ((-1)-(5))^{2} }$ </em>

<em> $Distance = \sqrt{61}$ </em>

<em>Distance = 7.8102 units</em>

To the nearest tenth, Distance = 7.8 units

3 0

3 years ago

30-[(9x2)-(3x4)] numerical expression ;)

alex41 [277]

30-[(9x2)-(3x4)]
30-[18-(3x4)]
30-(18-12)
30-6
24

4 0

3 years ago

Read 2 more answers

Can someone help not just whatever

bogdanovich [222]

4.) (the next prime function)
2x2x3x2
2x2x3x2x2
2x2x3x2x2x2

7 0

3 years ago

A huge Ping-Pong tournament is held in Beijing with 65,536 participants at the start of the tournament. Each round of

lisabon 2012 [21]

Answer:

After 16 rounds the champion of Ping-Pong player can be determined.

Step-by-step explanation:

This is an example of geometric progression,

First term = 65,536

$\texttt{Common ratio = }\frac{1}{2}$

Now we need to find which term is 1 in this GP.

N th term of GP is given by

$t_n=ar^{n-1}$

Substituting

$1=65536\times \left ( \frac{1}{2}\right )^{n-1}\\\\\frac{1}{65536}=\left ( \frac{1}{2}\right )^{n-1}\\\\2^{n-1}=65536\\\\2^{n-1}=2^{16}\\\\n=17$

Seventeenth term of this GP is 1.

That is after 16 rounds the champion of Ping-Pong player can be determined.

3 0

3 years ago