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Black_prince [1.1K]
2 years ago
14

Solve the inequality 2c/3 + 1 > 7

Mathematics
1 answer:
svp [43]2 years ago
6 0

Answer:

c > 9

Step by Step explanation

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An item on sale costs 25% of the original price. If the original price was $60 , what is the sale price?
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Answer:$45

Step-by-step explanation:

First you have to find 25% of 60

Which equals 15

60-15=45

$45

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For a two week period, John and Amanda had the following transactions occur to their checking account: a deposit of $1,644.50; c
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deposit of $1644.50 is (gain)

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4 0
3 years ago
When should I cross multiply fractions and when don’t I cross multiply?
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4 0
3 years ago
This was the question it got deleted I just need 1,2,5
scoundrel [369]

Answer:

1. The volume of the cylinder is 263 cm^{3}.

2. The volume of the cylinder is 12 m^{3}.

3. The volume of the cylinder is 3165.1 cm^{3}.

4. The radius of the cylinder is 3.6 cm.

5a. Area of the base is 50.2 cm^{2}.

5b. The curved surface area of the pencil holder is 351.7 cm^{2}.

5c. The surface are of the pencil holder is 452.2 cm^{2}.

Step-by-step explanation:

1. The given shape is a cylinder, so that;

volume of a cylinder = \pir^{2}h

                                  = 3.14 x (3.8)^{2} x 5.8

                                  = 262.98128

The volume of the cylinder is 263 cm^{3}.

2. This is also a cylinder, but with a given diameter.

radius = \frac{diameter}{2}

          = \frac{1.2}{2} = 0.6 m

volume of a cylinder = \pir^{2}h

                                  = 3.14 x (0.6)^{2} x 10.6

                                  = 11.98224

The volume of the cylinder is 12 m^{3}.

3. volume of a cylinder = \pir^{2}h

                                      = 3.14 x 6^{2} x 28

                                      = 3165.12

The volume of the cylinder is 3165.1 cm^{3}.

4. volume of a cylinder = \pir^{2}h

239 = 3.14 x r^{2} x 6

239 = 18.84 r^{2}

r^{2} = \frac{239}{18.84}

   = 12.6858

r = \sqrt{12.6858}

 = 3.5617

The radius of the cylinder is 3.6 cm.

5. Area of the base = \pir^{2}

radius = \frac{diameter}{2}

           = \frac{8}{2} = 4 cm

Area of the base = 3.14 x 4^{2}

                            = 50.24

Area of the base is 50.2 cm^{2}.

5b. Area of the curved surface of the pencil holder = 2\pirh

                                                                    = 2 x 3.14 x 4 x 14

                                                                     = 351.68

The curved surface area of the pencil holder is 351.7 cm^{2}.

5c. Surface area of the pencil holder = 2\pirh + 2\pir^{2}

                               = 2\pir(h + r)

                                = 2 x 3.14 x 4 (14 + 4)

                                = 452.16

The surface are of the pencil holder is 452.2 cm^{2}.

7 0
3 years ago
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