Answer:
-0.17157287525
Step-by-step explanation:
1. The square root of 8 will never be a whole number so it is 2.82842712475
2. Square root of 9 is 3.
3. You can already realize that the answer will not be whole or positive
4. Subtract in order.
5. The answer is -0.17157287525
Answer:
top row on 9 page; 9) 53/5 10) 26/4 11) 37/4
bottom row on 9 page; 9) 8 and 1/7 10) 6 and 3/4 11) 1 and 1/3
top row on 3 page; 3) 2 and 2/7 4) 5 and 3/4 5) 8 and 1/10
bottom row on 3 page; 3) 4/3 4) 3/2 5) 12/5
top row on 12 page; 12) 21/10 13) 62/6 14) 57/6
bottom row on 12 page; 12) 1 and 9/10 13) 10 and 1/2 14) 3 and 3/8
Step-by-step explanation:
You never specified if these had to be simplified or turned into a fraction, so I just simplified them. That's about it.
I hope this helps :)
(i just changed my answer)
sqrt is the square root of
v=sqrt(2(ke)/m)
Answer:
D
Step-by-step explanation:
∠1 + ∠2 = 180 {Supplementary angles}
6x + 15 + 3x + 3 = 180
6x + 3x + 15 + 3 = 180
Combine like terms
9x + 18 = 180
Subtract 18 from both sides
9x = 180 - 18
9x = 162
x = 162/9
x = 18
∠2 = 3x +3
= 3*18 + 3
= 54 + 3
∠2 = 57°
Answer:
the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Step-by-step explanation:
since the volume of a cylinder is
V= π*R²*L → L =V/ (π*R²)
the cost function is
Cost = cost of side material * side area + cost of top and bottom material * top and bottom area
C = a* 2*π*R*L + b* 2*π*R²
replacing the value of L
C = a* 2*π*R* V/ (π*R²) + b* 2*π*R² = a* 2*V/R + b* 2*π*R²
then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then
dC/dR = -2*a*V/R² + 4*π*b*R = 0
4*π*b*R = 2*a*V/R²
R³ = a*V/(2*π*b)
R= ∛( a*V/(2*π*b))
replacing values
R= ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm
then
L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm
therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
