Let us assume the gas bill of Paul in February = x dollars
Then
Electric bill of Paul for the month of February = (x/2) + 3
Amount of Electricity bill of Paul for the month of February = $92
then we can write the equation as
(x/2) + 3 = 92
x/2 = 92 - 3
x/2 = 89
x = 89 * 2
= 178 dollars
So the gas bill of Paul in February is $178. I hope this is the answer you were looking for.
<h3>Question:</h3>
<em>Jon is selling tickets for the school talent show. On the 1st day, he sold 3 senior tickets and 12 child tickets for $195. On the 2nd day he sold 13 senior tickets for $299. Find the price of a senior citizen ticket.</em>
<h3>Answer:</h3>
Create a system of equations to help you solve this problem. The system of equations will look like: 3s + 12c = 195 and 13s = 299. The variable s represents the cost of senior tickets and the variable c represents the cost of children tickets.

Solve the second equation for the variable s as this is the easiest way to solve the problem. Solve the second equation for s by dividing both sides of the equation by 13 to isolate the variable s.
s = 23
Since the question was only asking for the price of a senior citizen ticket, you are technically done. The first equation was only put there to confuse you or allow you to check your work if you needed to. The price of a senior citizen ticket (variable s) is $23.
Answer:
The answer is 50
Step-by-step explanation:
40-10=30
30+20=50
<span> y = 2/7 x - 1/7
slope = 2/7
</span><span>perpendicular lines, slope is opposite and reciprocal
</span>so slope of new line = -7/2
<span>passes through the point (9,-32)
</span><span>slope-intercept form: y = mx + b
so
b = y - mx
b = -32 - (-7/2)(9)
b = -32 + 63/2
b = -1/2
equation in </span>slope-intercept form:
y = -7/2 x - 1/2
D=10 a=5
5×5×π=25π
a=25π
2×5×π=10π
c=10π
c. C = 10π A = 25π