Question

The area formula for rectangular shapes is A=LW. What is the area of a rectangular shape with the dimensions of //tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B11%7D" id="TexFormula1" title="\sqrt[4]{11}" alt="\sqrt[4]{11}" align="absmiddle" class="latex-formula"> and $\sqrt[4]{3}$?

Answer 1

Hi!

Given the area formula ~ A = LW

We need to multiply the two values:

$\sqrt[4]{11} * \sqrt[4]{3}$

Since they have the same root, 4, we can multiply what's inside of the radical and give it the same root.

$11*3=33$

Now, we apply the same root as before:

$\sqrt[4]{33}$

Therefore, your answer is $\sqrt[4]{33}$

Now, if you need that as a numerical value rather than a radical, it's roughly $2.397$

Answer 2

Answer:

$\textsf{area}=\sqrt[4]{33}\:\textsf{square units}$

Step-by-step explanation:

Formula

Area of a rectangle = length × width

Given:

• $\textsf{length}=\sqrt[4]{11}$
• $\textsf{width}=\sqrt[4]{3}$

Substitute given values into the formula:

$\implies \textsf{area}=\sqrt[4]{11} \cdot \sqrt[4]{3}$

$\textsf{Apply radical rule}\quad\sqrt[n]{a} \cdot \sqrt[n]{b}=\sqrt[n]{ab}:$

$\implies \textsf{area}=\sqrt[4]{11 \cdot 3} =\sqrt[4]{33}\:\textsf{square units}$