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Debora [2.8K]
2 years ago
8

A cubical dice is thrown two times, find the probability that the outcomes is 5 in first throw and odd number in second throw.​

Mathematics
1 answer:
trapecia [35]2 years ago
8 0

All the numbers present in cubical dice = 6

  • ( 1 , 2 , 3 , 4 , 5 ,6 ) <u>Total Outcomes = 6</u>

<u>Probability = Favorable outcomes / Total number of outcomes </u>

  • Probability that 5 will come in first throw :-

<u>Favorable Outcomes = 1 </u>

<u>Favorable Outcomes = 1 Probability = 1/6</u>

  • Probability that an odd number will come in second throw :-

<u>Favorable Outcomes = 3</u>

<u>Probability = 3/6 ; 1/2</u>

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frozen [14]

Answer:

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Korvikt [17]

Answer:

L=\frac{1}{2}P-W

Step-by-step explanation:

Let's solve for L.

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Step 1: Flip the equation.

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Step 3: Divide both sides by 2.

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Answer:

L=\frac{1}{2}P-W

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