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3 years ago

3x3 systems answers 4x + 8y + z = 2 x + 7y - 3z = -14 2x - 3y + 2z = 3

Mathematics

1 answer:

klasskru [66]3 years ago

8 0

The last one is =z

hope this helps.

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HELP ME ASAP PLEASE?!?!

miss Akunina [59]

A True

Congruent means to have the same shape and size or when we can cut them out and then match them up completely.

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3 years ago

Read 2 more answers

Suppose the x intercept of the graph of y=f(x) are 2 and 3. what are the x-intercepts of y=8f(x)

Yuliya22 [10]

We are given: Function y=f(x).

First x-intercept of the y=f(x) is 2.

x-intercept is a point on x-axis, where y=0.

Replacing y by 0 and x by 2 in above function, we get

0=f(2)

Second x-intercept of the y=f(x) is 3.

Replacing y by 0 and x by 2 in above function, we get

0=f(3)

We are given another function y=8f(x).

Here only function f(x) is being multiplied with 8.

That is y values of function should be multiply by 8.

Because we have y value equals 0. On multiplying 8 by 0 gives 0 again and it would not effect the values of x's.

Therefore,

x-intercepts of y=8f(x) would remain same, that is 2 and 3.

6 0

3 years ago

Find ( f - g)(x).<br><br> f (x) = -2x2 - 2x - 3 and g(x) = 3x2 - 4x - 4

Kruka [31]

Answer:

$\large\boxed{(f-g)(x)=-5x^2+2x+1}$

Step-by-step explanation:

$(f-g)(x)=f(x)-g(x)\\\\\text{We have}\ f(x)=-2x^2-2x-3\ \text{and}\ g(x)=3x^2-4x-4.\\\\\text{Substitute:}\\\\(f-g)(x)=(-2x^2-2x-3)-(3x^2-4x-4)\\\\(f-g)(x)=-2x^2-2x-3-3x^2+4x+4\qquad\text{combine like terms}\\\\(f-g)(x)=(-2x^2-3x^2)+(-2x+4x)+(-3+4)\\\\(f-g)(x)=-5x^2+2x+1$

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3 years ago

All you need is on the photo

mariarad [96]

Answer:

$4^{-3}$

Step-by-step explanation:

$We\ are\ given\ that,\\4^4*4^{-8}*4\\We\ know\ that,\ for\ any\ real\ number\ n, n^a*n^b=n^{(a+b)}\\Hence,\\First,\ lets\ write\ all\ the\ terms\ in\ an\ exponential\ form.\\4^4*4^{-8}*4^1\\=4^{(4+(-8)+1)}\\=4^{(5-8)}\\=4^{-3}$

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3 years ago

a carpenter has been asked to build an open box with a sqaure base. the sides of the box will cost $3 per m^2 and the base will

slamgirl [31]

<h2>Dimension of box is 2 m x 2 m x 1.33 m</h2>

Step-by-step explanation:

Let a be base side and h be the height.

Volume of box, V = a²h

The sides of the box will cost $3 per m² and the base will cost $4 per m². Cost for making is $48.

That is

4a² + 3 x 4 x a x h = 48

4a² + 12 a x h = 48

a² + 3 ah = 12

$h=\frac{12-a^2}{3a}$

So volume is

$V=a^2\times \frac{12-a^2}{3a}=4a-\frac{a^3}{3}$

At maximum volume we have derivative is zero,

$dV=4da-3\times \frac{a^2}{3}da\\\\0=4-a^2\\\\a=\pm 2$

Negative side is not possible, hence side of square base is 2m.

Substituting in a² + 3 ah = 12

2² + 3 x 2 x h = 12

h = 1.33 m

Dimension of box is 2 m x 2 m x 1.33 m

5 0

3 years ago