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irina [24]
2 years ago
11

What is the product of 2.5 x 10^2 and 3.7 x 10^5 expressed in scientific notation?

Mathematics
1 answer:
Sergio039 [100]2 years ago
8 0

Answer:

Step-by-step explanation:

2.5 x 10^{2} * 3.7 x 10^{5}

add the expoents, and multiply the coefficients

2.5 * 3.7 =9.25

10^{2+5} = 10^{7}

9.25 x    10^{7}

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PLS HELP ASAP!!!
OverLord2011 [107]

Answer:

C I think I hope this helps

5 0
3 years ago
Subtract 5y^2 + 3y + 11 from 4y^2 + 7 - 6y.
lakkis [162]

Answer:

I got -y^2 - 9y -4 (I hope it helps)

Step-by-step explanation:

4y^2 - 5y^2= -y^2

7-11= -4

-6y + -3y= -9y

-y^2 -9y -4

6 0
3 years ago
The average ticket price for a concert at the opera house was $50. The average attendance was 4000. When the ticket price was ra
kotegsom [21]

Answer

given,

opera house ticket = $50

attendance = 4000 persons

now,

opera house ticket = $52

attendance = 3800 person

assuming these are the points on the demand curve

(x, p) = (4000,50) and (x,p) = (3800,52)

using point slope formula

p-50 = \dfrac{50-52}{4000-3800}(x - 4000)

p-50 = \dfrac{-2}{200}(x - 4000)

p-50 = \dfrac{-x}{100}+ 40

p = \dfrac{-x}{100}+ 90

R(x) = x . p

R(x) = x (\dfrac{-x}{100}+ 90)

R(x) = \dfrac{-x^2}{100}+ 90x)

\dfrac{d}{dx}(R(x)) = \dfrac{d}{dx}(\dfrac{-x^2}{100}+ 90x))

\dfrac{d}{dx}(R(x)) = (\dfrac{-2x}{100})+90)

at \dfrac{d}{dx}(R(x)) = 0

\dfrac{-2x}{100}= -90

x = 4500

\dfrac{d^2}{d^2x}(R(x)) = -ve

hence at x =4500 the revenue is maximum

for maximum revenue ticket price will be

p = \dfrac{-4500}{100}+ 90

p = $45

6 0
3 years ago
PLEASE HELP ⚠️⚠️
sattari [20]

Answer:

Elena could tell without finishing by simplifying both sides. The next step would have been 30x +24x = 30x+24. This would have been simplified down to x=1

Step-by-step explanation:

6 0
3 years ago
20 + 20= __________________
frozen [14]

Answer:

40

Step-by-step explanation:

Use long addition to evaluate.

3 0
3 years ago
Read 2 more answers
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