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2 years ago

Val needs to find the area enclosed by the figure. The figure is made by attaching

Mathematics

1 answer:

jolli1 [7]2 years ago

3 0

Answer: See below

Step-by-step explanation:

Radius of the semicircle = 46/2 = 23 m

$\therefore$ Area enclosed by the figure $=4 \times$ Area of semicircles + Area of square \begin{aligned} \\&=4 \times 3.14 \times(23)^{2} \times \frac{1}{2}+(46)^{2} \\&=3322.12+2116 \end{aligned} \\\\\\Area enclosed $=5438.12 \mathrm{~m}^{2}$$

So, Val might have have subtracted 2116 from 3322.12 instead of adding since 3322.12 - 2116 = 1206.12

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Roselyn is driving to visit her family, which live 150 150150 kilometers away. Her average speed is 60 6060 kilometers per hour.

Sauron [17]

Answer:

She can go 120 km before she runs out of fuel

It will take 2 hours.

Step-by-step explanation:

150 km is the distance

60 km/ h is the speed

The gas tank is 20 liters

We can go 6 km per liter

Fuel costs .60 dollars per liter

We need to determine how far she can go on a tank of gas

20 liters * 6 km / liter = 120 km

She can go 120 km before she runs out of fuel

120 km = 60 km/ h * x hours

Divide each side by 60

120/60 = x

2 hours

8 0

3 years ago

3(5b-1)=5<br> solve for b<br><br> 4(3y-1)=20<br> solve for y

Gnom [1K]

3(5b-1)=5
Get rid of the brackets
15b-3=5
add 3 to both sides of the equation
15b=8
divide both sides of the equation by 15
b=0.53

4(3y-1)=20
12y-4=20
12y=24
y=0.5

7 0

3 years ago

The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims

kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is $\mu=600$ , we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it $\sigma$ ) is

$\sigma=48$

Next they draw a random sample of n=70 students, and they got a mean score (denoted by $\bar x$ ) of $\bar x=613$

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis $H_0:\bar x \geq \mu$

- The alternative would be then the opposite $H_0:\bar x < \mu$

The test statistic for this type of test takes the form

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}$

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\$

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>

6 0

3 years ago

Read 2 more answers

G divided by 93 is 264

Tanya [424]

See picture for solution steps and answer.

4 0

3 years ago

Read 2 more answers

The height of a punted football can be modeled by the function: f(x) = -.0079 x2 + 1.8x + 1.5. In this equation, f(x) is the hei

mars1129 [50]

Answer:

Step-by-step explanation:

The function used to represent the height of a punted football can be modeled as

f(x) = -.0079x² + 1.8x + 1.5

Where f(x) is the height in feet, and x is the horizontal distance, also in feet.

a) when the ball was punted, x = 0, therefore, the height of the punted ball would be

f(x) = -.0079(0)² + 1.8(0) + 1.5

f(x) = 1.5 feet

The height is 1.5 feet

b) The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height reached by the punted ball.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = - 0.0079

b = 1.8

Vertex = - - 1.8/0.0079 = 227.84 feet

So the maximum height of the punt is 227.84 feet

3 0

3 years ago