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Ulleksa [173]
2 years ago
9

Quadratic functions g (x) and h (2) are graphed on the same coordinate gri

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
5 0
<h3>Since their vertices have the same x-value , solving their derivative equal to zero must give the same answer:</h3>

<h2>A & D are eliminated:</h2>

The derivative of h(x) in A is 2x+24

h'(x)=0 g'(x)=0

2x+24=0 2x=0

x=-12 x=0

Similarly the derivative of h(x) in D is 2x-24

h'(x)=0 g'(x)=0

x=12 x=0

<h3>Knowing that B & C give the same x-value when solving for the derivative=0</h3>

We know that the only difference comes down to the y-value when substituting x=0 in h(x).

The y-value of the vertex of h(x) must be +12 the y-value of the vertex of g(x).

We have to add 12 to get to the x-value, which means that the third option or C is your answer.

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Suppose Cotangent (theta) = StartFraction 5 Over 12 EndFraction, where Pi less-than theta less-than StartFraction 3 pi Over 2 En
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Answer:

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From the question;

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Kindly recall;

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to get hypotenuse, we will use Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides

let hypotenuse be h

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h^2 = 169

h = √169

h = 13

But sine theta = opposite/ hypotenuse = 12/13

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Consider posting each question separately, please.

Given   <span>-2.8k-4.31=-15.79 :

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2) Simplify the right side.
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