Answer:
30 s
Step-by-step explanation:
When the ball hits the ground h=0. To find the time t when this happens we must solve the equation h=0.
●h= 0
● -12t^2+360t =0
● t(-12t +360) = 0
● t = 0 or -12t +360 =0
● t=0 or -12t = -360
● t=0 or 12t =360
● t=0 or t=360/12
● t=0 or t= 30
The equation has two solutions.
The ball was fired with an initial speed of 800 feet per second so it cannot hit the ground at t=0.
So the ball hits the ground after 30 s.
Answer:
C.
0.5; 13.5; 1093.5
Step-by-step explanation:
Answer:
The answer would be 9(3+4)
Step-by-step explanation:
9(3+4)
= 9(3) + 9(4)
= 27 + 36
Answer:
Step-by-step explanation:
Given: 76,45,64,80,92
Required: Determine the standard deviation
We start by calculating the mean
Where x-> 76,45,64,80,92 and n = 5
Subtract Mean (71.4) from each of the given data
Determine the absolute value of the above result
Square Individual Result
Calculate the mean of the above result to give the variance
Hence, Variance = 255.298
Standard Deviation is calculated by 
Answer:
Correct answer: Hmax = 22.11 m
Step-by-step explanation:
The subject of this problem is a vertical shot upwards, to which the following formula applies:
V₀² - V² = 2 · g · H where is:
V₀ - initial velocity
V - final velocity
g = 10 m/s²
H - final height
Given:
V₀ = 69 ft/s = 21.03 m/s
V = 0 m/s
Hmax = ?
V₀² = 2 · g · Hmax ⇒ Hmax = V₀² / 2 · g
Hmax = 21.03² / 2 · 10 = 442.26 / 20 = 22.11 m
Hmax = 22.11 m
God is with you!!!
