Answer:
The dimensions of the rectangle = 60ft by 107ft
Where 60 ft = Width of the playing field
107ft = Length of the playing field
Step-by-step explanation:
A playing field is Rectangular is shape, hence,
The formula for Perimeter of a rectangle = 2(L + W)
P = 334 ft
L = 47 + W
W = W
Hence we input these values in the formula and we have:
334 = 2(47 + W + W)
334 = 2(47 + 2W)
334 = 94 + 4W
334 - 94 = 4W
240 = 4W
W = 240/4
W = 60
There fore, the width of this playing field = 60 ft
The length of this rectangle is calculated as:
47 + W
47 + 60
= 107 ft
The length of this playing field = 107ft
Therefore the dimensions of the rectangle = 60ft by 107ft
Answer:
(2x-4) = 12 ft
(6y + x) = 68
Step-by-step explanation:
If you look. It is exactly like the one across from it. Same measurements and everything.
(2x-4) = 12 ft
(6y + x) = 68 are your answers.
Let 
= -9, 
= -12 and so on.
-15 = -9 + (-6)
-15 = -9 + 2(-3)
Let -3 be the common difference, or <em>d</em>.
= -9 + n(-3)
= -9 - 3n
Answer:
m∠A + m∠B = 155
Step-by-step explanation:
ABC is an isosceles triangle that has a 130° angle at vertex B
then
m∠A = (180 - 130)/2 = 50/2 = 25 = m∠C
then
m∠A = m∠C = 25°
A-b
difference means subtract
