The triangles are simiar by AAA, so
k-6:5 + 4-k:6= 6k-36+20-5k:30 =
k-16:30
Answer
square root of 128 Lies between two square numbe
121 = 11 ^ 2
(11.1) ^ 2 = 133.1
So, √128 lies between 11.0 and 11.1.
<h3>Option A: 11.0 and 11.1
</h3>
Answer:
x - 3 = 0
Step-by-step explanation:
Click on this link, for I cant explain things very well :(
www.mathportal.org/calculators/analytic-geometry/two-point-form-calculator.php?val1=3&val2=4&val3=3&val4=8&rb1=gen