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Vaselesa [24]
3 years ago
9

If A = (0,0) and B = (2,5), what is the approximate length of AB?

Mathematics
2 answers:
Bad White [126]3 years ago
8 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AB=\sqrt{(2-0)^2+(5-0)^2}\implies AB=\sqrt{2^2+5^2} \\\\\\ AB=\sqrt{29}\implies AB\approx 5.39

Artist 52 [7]3 years ago
7 0

Answer:5.39 APEX

Step-by-step explanation:

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6 0
3 years ago
Help me fill this out thanks
alukav5142 [94]

Answer:

This is an isosceles right triangle, then we have

2 x u^2 = [6sqrt(2)]^2

<=> 2 x u^2 = 72

<=> u^2 = 36

<=> u = 6

Hope this helps!

:)

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4 years ago
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4 years ago
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insens350 [35]

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Step-by-step explanation:

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Now we have:

8w=72

Divide by 8 on both sides

8w cancels out to just w

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And you're left with:

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