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nikdorinn [45]
3 years ago
15

The probability of event A occurring is 10/10. The probability of event B occurring is 0/10. What is the entropy of this system?

Please show work.
Computers and Technology
1 answer:
IgorLugansk [536]3 years ago
5 0

The events A and B are the outcomes of the probabilities in the system

The entropy of the system is 0

<h3>How to determine the entropy?</h3>

The probabilities are given as:

P(A) = 10/10

P(B) = 0/10

The entropy is calculated using:

H(x) = -\sum \limits^{n}_{i = 1} p_i * \log_2(p_i)

So, we have

H(x) = -10/10 * \log_2(10/10) - 0/10 * \log_2(0/10)

Evaluate the products

H(x) = -\log_2(10/10) - 0

Evaluate the sum

H(x) = -\log_2(10/10)

Evaluate the quotient

H(x) =- \log_2(1)

Express 1 as 2^0

H(x) =- \log_2(2^0)

Apply the power rule of logarithm

H(x) =- 0\log_2(2)

Evaluate the product

H(x) =0

Hence, the entropy of the system is 0

Read more about probability at:

brainly.com/question/25870256

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