Answer:
A, C, and E
Step-by-step explanation:
For the first one, distribute -11 to each value. A negative times a negative is a positive, so -11×-2c is 22c. -11×-3d is 33d. So the first one is right. For the third one, distribute 1/3 to each value. 1/3 of 66c is 22c, and 1/3 of 99d is 33d, so the third one is correct as well. For the last one, distribute 11 again. 11×2c is 22c and 11×3d is 33d, so the last one is correct.
Answer:
1.66
Step-by-step explanation:
We need to conduct a chi square test
The statistic used to check this is given by the below
∑(n, 1) = [(O(i) - E(i)] / E(i)
From the question, we're told the observed value is
Freshmen
Sophomore
Junior
Senior.
After that, we then calculate the expected value.
Freshman
0.3 * 300 = $90
Sophomore
0.24 * 300 = $72
Statistics then finally gives us this
X² = (93 - 90²)/90 + (68 - 72)²/72 + (85 - 78)/78 + (64 -60)²/60
X² = 3² / 90 + 4² / 73 + 13² / 78 + 4² / 60
X² = 0.1 + 0.212 + 2.167 + 0.266 x+
X² = 2.745
X = √2.745
X = 1.66
The sum of two rational numbers will always be <u>rational</u>
<u></u>
, therefore it will always be rational
Answer is b if this helped please hook me up with brainiest answer
