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Your issue is on line 19 in your if statement. In python, if you have more than one condition in an if statement, you have to explicitly mention it after the or.
Your if statement is
if again == "Y" or "y":
However, this will always return true because the second statement simply asks "y".
To correct this, simply change the if statement to:
if again == "Y" or again == "y":
This will correct your code.
Another thing to consider is to always convert a userinput (whenever possible) to one version, this can be accomplished in your code by converting "again" into one version by using the .lower function.
again = input("Would you like to draw a 3rd card? Y or N? ")
again = again.lower()
Hope this helps!
??????? Can you explain the question some more
Answer:
True
Explanation:
In Computer science, It's true that injection attacks variants can occur whenever one program invokes the services of another program, service, or function and passes to it externally sourced, potentially untrusted information without sufficient inspection and validation of it.
