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2 years ago

How do latitude and longitude help identify your exact location?

SAT

1 answer:

gladu [14]2 years ago

3 0

Answer:

The lines of longitude and latitude help us in measuring the distance from the Earth's Equator.

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A 0.1 kg block of brass is cooled until it releases 56.4 J of heat. If the temperature of the block was 5 K initially, what is i

Zolol [24]

Answer:

3.5 K

Explanation:

When a sample of a substance releases heat energy, its temperature decreases according to the equation:

$Q=mC(T_f-T_i)$

where

Q is the heat energy released

m is the mass of the substance

C is the specific heat capacity

$T_i$ is the initial temperature

$T_f$ is the final temperature

For the block of brass in this problem, we have:

m = 0.1 kg is the mass

Q = -56.4 J is the heat energy released (negative since it is released)

C = 380 J/kg K is the specific heat capacity of brass

$T_i=5 K$ is the initial temperature

Solving for $T_f$ , we find the final temperature:

$T_f=T_i + \frac{Q}{mC}=5+\frac{-56.4}{(0.1)(380)}=3.5 K$

5 0

3 years ago

Select the letter of the correct answer. There is a large, empty rectangle. Above the rectangle, it says Main Idea of the Articl

Nataly_w [17]

Answer:

lol

Explanation:

i need this too !

6 0

3 years ago

A sample of aluminum metal absorbs 9. 86 j of heat, upon which the temperature of the sample increases from 23. 2°c to 30. 5°c.

Alenkinab [10]

Answer:

you can do it

Explanation:

ok ok?! or not?

7 0

2 years ago

the height of a bottle rocket, in meters, is given by the function s(t)=−9t2+103t+403. find the average velocity of the bottle r

zaharov [31]

The average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

The given parameters;

s(t) = -9t² + 103t + 403
time interval (4.499, 4.5), and (4.5, 4.501)

The average velocity of the bottle rocket over the intervals is calculated as follows;

when the interval = [<em>4.499, 4.5</em>]

$s(4.499)= -9(4.499)^2 + 103(4.499) + 403 = 684.22 \ m\\\\s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m$

$v = \frac{\Delta \ s}{\Delta \ t} = \frac{684.25 - 684.22}{4.5 - 4.499} = 30 \ m/s$

when the interval = [<em>4.5, 4.501</em>]

$s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m\\\\s(4.501) = -9(4.501)^2 + 103(4.501) + 403 =684.27 \ m\\\\v= \frac{684.27 - 684.25}{4.501-4.5} \\\\v = 20 \ m/s$

The instantaneous velocity of the bottle rocket at time t=4.5;

$v = \frac{d \ s(t)}{dt} = -18t + 103\\\\v(4.5) = -18(4.5) + 103\\\\v(4.5) = 22 \ m/s$

Thus, the average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

Learn more here: brainly.com/question/25009886

7 0

2 years ago

Is this sentence in active voice or passive voice?

dusya [7]

Answer:

Passive Voice

Explanation:

I just did a 50/50 chance and got it right.

6 0

3 years ago